Math, asked by mani9427, 1 year ago

find the greatest numbers that will divide 90,54 and 78 leaving a remainder 6 in each case.​

Answers

Answered by waddu
0

Answer:

let us first subtract 6 from each no.

90-6=84

54-6=48

78-6=72

now find HCF of 84, 48, & 72

HCF is 12

the answer is 12

Answered by priyanshualok5841
0

Step-by-step explanation:

so let's first of all remove 6 from each number then find their HCF

hcf(86.74.50) = 2

since 74 = 2 \times 37 \\ </p><p>86=2 \times 23 \\ 50 = {5}^{2}  \times  {2}^{1}

okay I agree I'm wrong. how will I delete my answer?

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