find the greatest numbers which divides 615 and 963.Leaving the reminder 6 in each case
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To find the largest no. which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.
let HCF be x
In order to make 615 and 963 completely divisible by x , we need to deduct the remainder 6 from both the cases.
609=3,3,29
957=3,11,29
so,x=87
therefore,87 is the largest no.
let HCF be x
In order to make 615 and 963 completely divisible by x , we need to deduct the remainder 6 from both the cases.
609=3,3,29
957=3,11,29
so,x=87
therefore,87 is the largest no.
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