Question

find the greatest six digit number exactly divisible by 24,15and36

Answer 1

Heya !!

Here's your answer.. ⬇⬇

Greatest six digit no. is = 999999

Find L.C.M of 24, 15 and 36.

24 = 2 × 2 × 2 × 3

15 = 3 × 5

36 = 2 × 2 × 3 × 3

L.C.M = 2 × 2 × 2 × 3 × 3 × 5

= 360

Now, divide 999999 by 360

= 999999/360
= 2777.777..
= 2777 ( approx. )

Multiplying L.C.M 360 by 2777 we get..

= 2777 × 360
= 972220

Now,

972220/24 = 41655

972220/15 = 66648

972220/36 = 27770

972220 is divisible by 15, 24, and 36.

972220 is the greatest no. divisible by 15, 24 and 36.


Hope it helps..

Thanks (:

Answer 2

hye

==================================

we have to find  the greatest six digit number exactly divisible by 24,15and36

=>first let us find the lcm of 24,15 and 36

=>prime factorisiation of 24 =  2*2*2*3

prime factorisiation of 15=  5*3

prime factorisiation of 36=   2*2*3*3 


common factors =  5*2*2*2*3*3 = 360.

lcm = 360

greatest 6 digit = 999999

=>now lets divide 999999/360

=>2777.775

=>2777 aprrox

=>2777*360

=>999720


check:-

 999720 / 24 = 41655

999720/15=66648

999720/36=27770

==================

hope it helps u........