Find the greatest six digit number that will be divided by 15,25 and 30 leaves no remainder.
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Answered by
5
Answer:
It's 999960.
For this you will need to find the lowest common multiple of the three numbers.
Lcm of 15,24,30=120(3*5*2*2*2)
Largest 6 digit number =999999.
Next we divide it by the Lcm.
Dividing it by 120 we get 999999/120=8333.325
Hence the largest number divisible by 120 =8333*120=999960
Answered by
14
Answer:
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Step-by-step explanation:
Answer: It's 999960. For this you will need to find the lowest common multiple of the three numbers. Largest 6 digit number =999999
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