Math, asked by swayamshreemoh78, 3 months ago

Find the greatest six digit number that will be divided by 15,25 and 30 leaves no remainder.

Answers

Answered by Anonymous
5

Answer:

It's 999960.

For this you will need to find the lowest common multiple of the three numbers.

Lcm of 15,24,30=120(3*5*2*2*2)

Largest 6 digit number =999999.

Next we divide it by the Lcm.

Dividing it by 120 we get 999999/120=8333.325

Hence the largest number divisible by 120 =8333*120=999960

Answered by Anonymous
14

Answer:

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Step-by-step explanation:

Answer: It's 999960. For this you will need to find the lowest common multiple of the three numbers. Largest 6 digit number =999999

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