Find the greatest three-digit number which is divisible by 5.
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Step-by-step explanation:
The smallest and the largest numbers of three digits, which are divisible by 5 are 100 and 995 respectively,
So, the sequence of three digits numbers which are divisible by 5 is 100,105,110,...,995.
It is an AP with first term a=100 and common difference d=5.
Let there be n terms in this sequence. Then,
a
n
=995⇒a+(n−1)d
995=100+(n−1)×5
⇒n−1=179
⇒n=180
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Answered by
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Answer:
Your answer is 995.
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