Find the greatest which divides 81 and 292 leaving remainder 3 in each case.
Answers
Answered by
1
Solution: 81–3 = 78
292–3 = 289
Factors of
78 = 2x3x13
289 = 17X17
The HCF of 78 and 289 is 1.
81/1 = 81 and 292/2= 292.
When the divisor is 1 can the remainder by 3?
The question is wrong.
There is no such number. Answer.
Answered by
1
Answer:
LCM of 81 and 292
Step-by-step explanation:
is 18,396+3= 18399
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