find the gretest number of five digits which is exactily divisible by 20,25,28,35,40.
Answers
Answer:
The required number is 98280 which is exactly divisible by 20,24,35 & 45.
Step-by-step explanation:
To find : The Greatest 5 digit number exactly divisible by 20,24,35 & 45?
Solution :
The greatest 5-digit number is 99999.
We find the LCM of 20,24,35 & 45.
2 | 20 24 35 45
2 | 10 12 35 45
2 | 5 6 35 45
3 | 5 3 35 45
3 | 5 1 35 15
5 | 5 1 35 5
7 | 1 1 7 1
| 1 1 1 1
LCM(20,24,35,45)=2\times 2\times 2\times 3\times 3\times 5\times 7LCM(20,24,35,45)=2×2×2×3×3×5×7
LCM(20,24,35,45)=2520LCM(20,24,35,45)=2520
Divide 99999 by 2520 so that we get the remainder,
99999 = 39 \times 2520 + 171999999=39×2520+1719
Remainder is 1719.
Now, Subtract the remainder from 99999.
99999-1719=9828099999−1719=98280
Therefore, The required number is 98280 which is exactly divisible by 20,24,28,35and40