Question

Find the growth cycle of 2 years at a rate of 10% per annum of 1800 rupees​

Answer 1

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The compound interest on Rs 1800 at 10 % per annum for a certain period of time is Rs 378. Find the time in years.

Answer

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Correct option is

A

2

P=Rs.1800

R=10%

C.I.=Rs.378

A=P+C.I=Rs.(1800+378)=Rs.2178

We know,

A=P(1+

100

R

)

n

⇒ 2178=1800(1+

100

10

)

n

⇒

1800

2178

=(1+

10

1

)

n

⇒ 1.21=(

10

11

)

n

⇒ (1.1)

2

=(1.1)

n

By comparing we get,

⇒ n=2 years

Answer 2

Answer:

$simple \: intrest \: = \frac{p \times r \times t}{100} \\ p = 1800rs. \\ r = 10\% \\ t = 2 \: years \\ \frac{1800rs. \times 10\% \times 2}{100} \\ = 180 \times 2rs. = 360rs.$

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360rs.+1800rs.= 2160rs.