Find the guadratic polynomial,sum of whose zeroes is 8 and their product is 12 hence find the zeroes of the polnomial
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Answer:
zeroes are 6, 2
Step-by-step explanation:
let zeroes be α and β
According to question:
α+β=8
⇒ α = (8-β)
And,
α×β=12
Substituting value of α we get
(8-β)×β=12
8β - β²=12
β²-8β+12=0
⇒ β²-6β-2β+12=0
⇒ β (β-6) -2 (β-6)=0
⇒ (β-2)(β-6)=0
∴β= 2, 6
∴α= (8-2) , (8-2) = 6, 2
∴when α=6, β=2 and when α=2, β=6
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