Question

Find the guadratic polynomial whose zeros are -9 and 1/-9

Answer 1

Answer:

K [9x² + 82 + 9]

Step-by-step explanation:

α = -9

β = -1/9

α + β = -9 + (-1/9)

         = -82/9

αβ = -9 * (-1/9)

     = 1

Polynomial = K [x² - (α+β)x + αβ]

K here is a constant

==: K [x² - (-82/9)x + 1]

==: K [x² + 82x/9 + 1]

==: K [9x² + 82 + 9]

Pls mark my answer as brainlist

Pls follow me