Find the H.C.F and L.C.M of:
i) a^2 - ax, x^2 – 2ax + a² and x^2 - a^2
Answers
Answered by
0
Answer:
ANSWER
x3 + (a +b)x2 + (ab + 1)x + b
= x3 + (a +b)x2 + abx + x + b
= x [x2 + (a + b)x + ab] + (x + b)
= x (x + a) (x + b) + (x + b)
= (x + b) [x (x + a) + 1]
= (x + b) (x2 + ax + a)
x 3 + 2ax 2 + (a 2 + 1)x + a
= x3 + 2ax2 + a 2 x + x + a
= x (x 2 + 2ax + a 2 ) + (x + a)
= x (x + a) (x + a) + (x + a)
= (x + a) [x (x + a) + 1]
= (x + a) (x 2 + ax + 1)
Common factor between the two polynomials = x 2 + ax + 1
∴ HCF = x 2 + ax+1
Similar questions