find the H.C.F and the L.C.M of each of the following. @2ab, 3ac,4bc please tell me. and its ans is H.C.f =c,L.C.M. 12 abc
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Answer:
We know that the least common multiple (LCM) is the smallest number or expression that is a common multiple of two or more numbers or algebraic terms.
We first factorize the given monomials a
2
bc,b
2
ac and c
2
ab as shown below:
a
2
bc=a×a×b×c
b
2
ac=b×b×a×c
c
2
ab=c×c×a×b
Now multiply all the factors, using each common factor only once, therefore, the LCM is:
a×a×b×b×c×c=a
2
b
2
c
2
Hence, the LCM of a
2
bc,b
2
ac and c
2
ab is a
2
b
2
c
2
.
Step-by-step explanation:
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