Math, asked by MarwanAhmed, 15 days ago

Find the H.C.F. by long division method are 90 35​

Answers

Answered by tanjotk96
0

95 = 35 x 2 + 25

35 = 25 x 1 + 10 (divisor of previous step becomes dividend of new step and remainder of previous step becomes divisor of new step)

25 = 10 x 2 + 5

10 = 5 x 2 + 0 (stop when remainder is 0)

The previous remainder is the HCF

Hence, the required HCF is 5

Answered by sishilkumar1920
0

Answer:

is the twenty please mark as brilliant.

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