Find the H.C.F. by long division method are 90 35
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95 = 35 x 2 + 25
35 = 25 x 1 + 10 (divisor of previous step becomes dividend of new step and remainder of previous step becomes divisor of new step)
25 = 10 x 2 + 5
10 = 5 x 2 + 0 (stop when remainder is 0)
The previous remainder is the HCF
Hence, the required HCF is 5
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Answer:
is the twenty please mark as brilliant.
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