Math, asked by purvivaishnava9, 5 months ago

Find the H.C.F of 14x3y , 21xy5

Answers

Answered by bagkakali

1

Answer:

1st term=14x^3y=2*7*x*x*x*y

2nd term=21xy^5=7*3*x*y*y*y*y*y

H.C.F=7*x*y=7xy

Step-by-step explanation:

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