Question

Find the H.C.F. Of 18,54,81 by using division method

Answer 1

to find the answer make a table for division method.

Your 1st number is 18.

Find its factors.

2 times 9 is 18

3 times 3 is 9

3 times 1 is 3

so your factors are = 2X3X3

Next number is 54

so its factors are

2 times 27 is 54

3 times 9 is 27

3 times 3 is 9

3 times 1 is 3.

so your factors are = 2X3X3X3

last number is 81

factors are:

3 times 27 is 81

3 times 9 is 27

3 times 3 is 9

3 times 1 is 3

your factors are = 3X3X3X3

NOW PUT THEM ALL TOGETHER:

Factors of 18 =2X3X3

Factors of 54 = 2X3X3X3

Factors of 81 =3X3X3X3

Now look for common factors which are all present in all 3 rows.

3 is present once

3 is present again.

match the common by encircling how many times 3 is common in all 3 rows.

twice.

now you see that 3X3 is common in all three rows.

thats your answer, 3 times 3 = 9.

your HCF is 9

Answer 2

first find prime factors of 18 54 81 and then check the HCF it will be 6 so your answer is 6 thank you hope so it helps you