Question

Find the H•C•F of 184,230and 276 of long diviesn method​

Answer 1

Answer:

So, the divisor at this or the remainder at the previous stage i.e., 46 is the HCF of 184 and 230. Hence, the required HCF of 184, 230 and 276 is 46.

hope it helps you

Answer 2

Answer attached in this pic

plz mark as brainliest