Question

Find the H.C.F. of: 2² x 3³ x 5², 3² x 5³ x 7 and 2 x 3² x 5² x 7. Leave your answer in INDEX FORM.

Answer 1

To Find :- H.C.F. of: 2² x 3³ x 5², 3² x 5³ x 7 and 2 x 3² x 5² x 7 ?

Solution :-

We know that,

• HCF(Highest common factor) :- Is the greatest number which divides exactly the given numbers .

So,

→ First number = 2² x 3³ x 5² = 2 × 2 × 3 × 3 × 3 × 5 × 5

→ Second number = 3² x 5³ x 7 = 3 × 3 × 5 × 5 × 5 × 7

then,

→ Common factors are = 3 × 3 × 5 × 5

therefore,

→ HCF = Product of common factors .

→ HCF = 3 × 3 × 5 × 5

→ HCF = 225

hence, writing HCF in index form ,

→ HCF = 3² × 5² (Ans.)

Learn more :-

find the expanded form of 253.147

https://brainly.in/question/29654250

(3) निम्न के स्थानीय मान लिखिये-

(अ)43.24

(स)884.20

(ब) 534.34

(द) 178.34

https://brainly.in/question/37666224

Answer 2

Answer:

The HCF of $2^2*3^3*5^2$ , $3^2*5^3*7$ , $2*3^2*5^2*7$ is $225$

Step-by-step explanation:

Given:

The factored form of three numbers as

$2^2*3^3*5^2$

$3^2*5^3*7$

$2*3^2*5^2*7$

We need to find the HCF

The highest common factor (HCF) is found by finding all common factors of the numbers and selecting the largest one.

So the HCF is $3^2*5^2=225$