Question

Find the H.C.F. of 22 x 33 x55 23 x32 x 52 x7 and 24 x 34 x 5x72 x11​

Answer 1

QUESTION:

H.C.F OF 2² × 3³ × 5^5 × 2³ × 3² × 5² × 7

                          AND

                2^4 × 3^4 × 5 × 7² × 11

= 2^5 × 3^5 × 5^7 × 7      &      2^4 × 3^4 × 5 × 7² × 11

= 2^4 × 3^4 ×5 × 7

= 16 × 81 × 35

= 45, 360

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