Math, asked by sahayasajith3, 9 months ago

Find the H.C.F of 2power3*3power2*5*7power5 and 2power2*3power2*5power2*7 and 2power4*5power3*7power5

Answers

Answered by Anushka0602
3

Answer:

2^3×3^2×5×7^5

2^2×3^2×5^2×7

2^4×5^3×7^5

HCF = 2^2×5^2×7

= 4×25×7

= 100×7

= 700

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