Question

Find the H. C. F of 4×27×3125, 8×9×25×7and 16×81×5×11×49?​

Answer 1

Answer:

1st number = 2^2 x 3^3 x 5^5 x 7^0 x 11^0

2nd number = 2^3 x 3^2 x 5^2 x 7^1 x 11^0

3rd number = 2^4 x 3^4 x 5^1 x 7^2 x 11^1

Then we take the lowest exponent for all the prime factors

They are:

2^2

3^2

5^1

7^0 (note that for 7 and 11, the lowest exponent is 0 not 1)

11^0

Multiply them all for the HCF

HCF = 2^2 x 3^2 x 5^1 x 7^0 x 11^0 = 4 x 9 x 5 x 1 x 1 = 180

Step-by-step explanation:

please mark me brainliest and follow me

Answer 2

Answer:

yaar into kake HCF nikalo please follow me