Question

Find the H.C.F of 40,56 and 60 by continued division method?

Answer 1

Answer:

HCF = 2

Step-by-step explanation:

HOPE YOU GOT YOUR DESIRED ANSWER. PLEASE MARK ME AS BRAINLIEST.

Answer 2

Answer:

We \:have ,Wehave,

\begin{gathered}40 = 2\times 2 \times 2 \times 5 = 2^{3} \times 5^{1}\\ 56 = 2 \times 2\times 2 \times 7 = 2^{3} \times 7^{1} \\ 60 = 2\times 2 \times 3 \times 5 = 2^{2} \times 3^{1} \times 5^{1}\end{gathered}

40=2×2×2×5=2

3

×5

1

56=2×2×2×7=2

3

×7

1

60=2×2×3×5=2

2

×3

1

×5

1

HCF (40,56,60) = 2^{2}HCF(40,56,60)=2

2

/* Product of the smallest power of each common prime factors of the numbers */

Therefore.,

\{HCF (40,56,60)}\{= 4 }HCF(40,56,60)=4