Find the H.C.F of 420 and 130 by Euclid's division lemma
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Answered by
204
420>130
420 = 130×3+30
130 = 30×4+10
30 = 10×3+0
therefore 10 is hcf of 420 and 130
420 = 130×3+30
130 = 30×4+10
30 = 10×3+0
therefore 10 is hcf of 420 and 130
Answered by
91
Hi Deepika ^_^
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Two numbers as 420 and 130
Apply Euclid's Division Lemma on 420 and 130
420=130 x 3+30
as r≠ 0 so again apply Euclid's division Lemma on 130 and 30
130= 30 X 4+10
as r≠ 0 so again apply Euclid's division Lemma on 30 and 10
30 = 10 X 3 + 0
As r=0 so HCF = 10
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-SahilLincoln
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Two numbers as 420 and 130
Apply Euclid's Division Lemma on 420 and 130
420=130 x 3+30
as r≠ 0 so again apply Euclid's division Lemma on 130 and 30
130= 30 X 4+10
as r≠ 0 so again apply Euclid's division Lemma on 30 and 10
30 = 10 X 3 + 0
As r=0 so HCF = 10
___________________________________________________________________________________________________________________________
-SahilLincoln
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