Find the H.C.F of 65 and 117 and express it in the form 65x+117Y. easiest way
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Let us find the HCF of 65 and 117,
= 117 = 1 × 65 + 52
= 65 = 1 × 52 + 13
= 52 = 4 ×13 + 0
Therefore HCF of 65 and 117 is 13.
= 65m -117 = 13
= 65m = 117+13 = 130
= m =130 / 65 =2
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