Find the H.C.F of 65 and 117 and express it in the form of 65x×117y.
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Hey friend, Harish here.
Here is your answer:
Euclid's Division Lemma states that,
a = b ( q ) + r.
Here.
117 = 65 × 1 + 52
65 = 52 × 1 + 13
52 = 13 × 4 + 0
Therefore 13 is the HCF.
Then we know that,
13 = 65 - (52 × 1) .
And , 52 = 117 - ( 65 × 1 )
Then, 13 = 65 - (117 - 65 × 1)
⇒ (65 × 2) - 117. = 65x - 117y
Now by comparing we get.
x = 2, y = 1.
_______________________________________________
Hope my answer is helpful to you.
Here is your answer:
Euclid's Division Lemma states that,
a = b ( q ) + r.
Here.
117 = 65 × 1 + 52
65 = 52 × 1 + 13
52 = 13 × 4 + 0
Therefore 13 is the HCF.
Then we know that,
13 = 65 - (52 × 1) .
And , 52 = 117 - ( 65 × 1 )
Then, 13 = 65 - (117 - 65 × 1)
⇒ (65 × 2) - 117. = 65x - 117y
Now by comparing we get.
x = 2, y = 1.
_______________________________________________
Hope my answer is helpful to you.
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