Question

Find the H.C.F of 9/10, 12/25, 18/35, 21/40​

Answer 1

Answer:

$Correct option is</p><p></p><p>C</p><p></p><p>3/1400</p><p></p><p>H.C.F of  fractions=L.C.MofdenominatorH.C.Fofnumerator</p><p></p><p>=L.C.M(10,25,35,40)H.C.F(9,12,18,21)</p><p></p><p>Factors of 9=3×3</p><p></p><p>Factors of 12=3×2×2</p><p></p><p>Factors of 18=3×3×2</p><p></p><p>Factors of 21=3×7</p><p></p><p>Common factor=3</p><p></p><p>∴ H.C.F=3</p><p></p><p>Factors of 10=5×2</p><p></p><p>Factors of 25=5×5</p><p></p><p>Factors of 35=5×7</p><p></p><p>Factors of 40=5×2×2×2</p><p></p><p>L.C.M=1400</p><p></p><p>H.C.F=14003</p><p></p><p>$

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