Question

Find the H.C.F of a^3-9a, a^2+a-6 and a^4+27a

Answer 1

on the number line - 5 on blank side of -12

Answer 2

Answer:

${a}^{3} - 9a = a( {a}^{2} - 9) \\ = a( a- 3)(a + 3) \\ {a}^{2} + a - 6 = (a + 3)(a - 2) \\ {a}^{4 } + 27a = a( {a}^{3 }+ 27) \\ = a(a + 3)( {a}^{2} - 3a + 9) \\ hcf = (a + 3)$

Step-by-step explanation:

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