Find the H.C.F. of (i) two prime numbers; (ii) twoconsecutive numbers; (iii) two ... H.C.F. andL.C.M. of two numbers are 9 and 270 respectively. If one of the numbers is 45, find the other number.
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(i) Hcf of two prime nos. Is always = 1
(ii) Same with two consecutive nos.
(iii) [HCF * LCM] of the two given numbers = Product of the two given nos.
Therefore, the other no. =
(HCF * LCM) / the given no.
= (9 * 270) / 45 = 54
(ii) Same with two consecutive nos.
(iii) [HCF * LCM] of the two given numbers = Product of the two given nos.
Therefore, the other no. =
(HCF * LCM) / the given no.
= (9 * 270) / 45 = 54
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