Question

Find the H.C.F of the following polynomials.
a) 10(x2 – 1) and 15(x + 1)^(2x + 3)​

Answer 1

Answer:

5 is the H.C.F I hope that it will be helpful to you

Answer 2

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

H.C.F of [p(x), g(x)] = 5(x + 1).

Solution:

Given two Polynomials,

• p(x) = 10(x² - 1)

• q(x) = 15(x + 1)⁴ (2x + 3)

⇒ p(x) = 10(x² - 1²) = 2 × 5 (x + 1) (x - 1)

⇒ q(x) = 15(x + 1)⁴ (2x + 3) = 3 × 5 (x + 1) (x + 1) (x + 1) (x + 1) (2x - 3)

H.C.F of [p(x), g(x)] = 5 (x + 1) .

Hope It'll Helps!