Find the H.C.F of the following polynomials.
a) 10(x2 - 1) and 15(x + 1)^(2x + 3)
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Thus HCF( p,q)=5(x+1)
Step-by-step explanation:
a) 10(x² - 1) and 15(x + 1) ^ (2x + 3)
We assume followings
p=2*5(x²-1)=2*5( x+1)(x-1)...........(1)
let 2x+3=y
q=3*5(x+1)^y.............................(2)
From(1) and (2) we find
common factor are : 5(x+1)
Thus HCF( p,q)=5(x+1)
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