Math, asked by mujeebtetra, 9 months ago

Find the H.C.F of the following polynomials.
a) 10(x2 - 1) and 15(x + 1)^(2x + 3)​

Answers

Answered by mathdude500
3
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Answered by Anonymous
2

Answer:

Thus HCF( p,q)=5(x+1)

Step-by-step explanation:

a) 10(x² - 1)  and  15(x + 1) ^ (2x + 3)​

We assume followings

p=2*5(x²-1)=2*5( x+1)(x-1)...........(1)

let 2x+3=y

q=3*5(x+1)^y.............................(2)

From(1) and (2) we find

common factor are : 5(x+1)

Thus HCF( p,q)=5(x+1)

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