find the h.c.f of the terms in the expression 3a2b2 + 6ab2c2 + 12a2bc3.
Answers
Answered by
1
Answer:
1st we take common from each expression
3a2b2=3 a b
6ab2c3=3 a b
12a2b2c3 =3 a b
so hcf is
3xaxb
Similar questions