find the H.C.F of the x^3+3x^2-16x+12 by division method
Answers
Answered by
1
Answer:
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(((x3) - 3x2) - 16x) - 12
STEP
2
:
Checking for a perfect cube
2.1 x3-3x2-16x-12 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: x3-3x2-16x-12
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -16x-12
Group 2: x3-3x2
Pull out from each group separately :
Group 1: (4x+3) • (-4)
Group 2: (x-3) • (x2)
Answered by
2
Answer:
(x+2)
Step-by-step explanation:
Factor of the equation are.
(x + 2) • (x + 1) • (x - 6) = 0
so, x+2 is the largest factor among all.
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