Question

Find the H.C.F. of:
x(x+1) -y(y+1), y(x + y) – (1+x),(y+ 1) – x(x + y)

Answer 1

Step-by-step explanation:

x(x+1) -y(y+1) = x²+x - y²-y

y(x + y) – (1+x) = xy+y² - 1-x

(y+ 1) – x(x + y) = y+1-x²-xy

HCF = x , y = x+y

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