find the H.C.F of :- x2-3x+2 and x2-4x+3.
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p(x)= x cube minus 3 X + 2
x(x2-3+2)
x(x2-1)
x(x-1)(x+1)
q(x)=x2+4x+3
x2-3x-x+3
x(x-3)-1(x -3)
(x-1)(x-3)
we found common is P of X and q of x is equal to X - 1
x(x2-3+2)
x(x2-1)
x(x-1)(x+1)
q(x)=x2+4x+3
x2-3x-x+3
x(x-3)-1(x -3)
(x-1)(x-3)
we found common is P of X and q of x is equal to X - 1
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