Question

find the H.C. F of405and2520​

Answer 1

hyyyy

here's u r answer

the answer is 45

❣️❣️hope this helps you ❣️❣️

Answer 2

Answer:

hii

your answer is here !

Step-by-step explanation:

$Hi ,</p><p></p><p></p><p></p><p>Let a and b any two positive integers . Then there exist two</p><p></p><p>unique q and r such that</p><p></p><p>a = bq + r ,</p><p></p><p>0 less or equal to ' r ' less than b.</p><p></p><p></p><p>a ) 405 and 2520 , start with the larger integer that is , 2520</p><p></p><p>Apply the division lemma to 2520 and 405 , </p><p></p><p>2520 = 405 × 6 + 90</p><p></p><p>Since the remainder 90 , we apply the division lemma to</p><p></p><p>405 and 90</p><p></p><p>405 = 90 × 4 + 45</p><p></p><p>90 = 45 × 2 + 0</p><p></p><p>The remainder has now become zero, so procedure stops.</p><p></p><p>Therefore , </p><p></p><p>HCF( 405 , 2520 ) = 45.$

follow me !