Question

find the h.c.fof 144,180, and 252​

Answer 1

Answer:

12 is the ans

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Answer 2

Answer:

36

Step-by-step explanation:

Prime factors of 144 =

${2}^{2} \times \ {3}^{2}$

Prime factors of 180 =

${2}^{2} \times {3}^{2} \times 5$

prime factor of 252=

${2}^{2} \times {3}^{2} \times 7$

Common prime factors with the lowest exponent:

${2}^{2} \times {3}^{2}$

HCF= 4×9 =36