Question

find the half life period of first order reaction whose rate constant k=4.93×10powermines4 spowermines1​

Answer 1

t1/2=.693/k

so =.693/4.93 *10^-4

1.405*10^3 is ur ans mark me brainlist

if it helps you

Answer 2

The half life of the given reaction is $1.41\times 10^{3}min$

Explanation:

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = ? min

k = rate constant of the reaction = $4.93\times 10^{-4}min^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{4.93\times 10^{-4}min^{-1}}=1.41\times 10^{3}min$

Learn more about first order kinetics:

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