Find the half range sine series for f(x)=x in(0,π)
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∀x∈(0.. π):f(x)=cosx. Let f be expressed by a half-range Fourier sine series: f(x)∼∞∑n=1bnsinnπxλ
Answered by
0
Answer:
∀x∈(0.. π):f(x)=cosx. Let f be expressed by a half-range Fourier sine series: f(x)∼∞∑n=1bnsinnπxλ
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