Question

Find the HCE and Lom of 6. 72 and 120,
using
the prime factorisation Method​

Answer 1

Step-by-step explanation:

We have : 6=2×3,72=2

3

×3

2

,120=2

3

×3×5

Here, 2

1

and 3

1

are the smallest powers of the common factors 2 and 3 respectively.

So, HCF(6,72,120)=2

1

×3

1

=2×3=6

2

3

,3

2

and 5

1

, are the greatest powers of the prime factors 2,3 and 5 respectively involved in the three numbers.

So, LCM(6,72,120)=2

3 ×3²×5 ¹

= 360

Answer 2

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6 = 2 × 3

72 => 2 × 2 × 2 × 3 × 3 = 2³ × 3²

120 => 2 × 2 × 2 × 3 × 5 = 2³ × 3¹ × 5¹

HCF(6,72,120) => 2¹ × 3¹ = 6

LCM(6,72,120) => 2³ × 3² × 5¹ = 360