find the HCF... 132, 154, 176 (Division Method)
iii) 12, 24, 36 (Common factor Method / Listing Method) please help its really urgent
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Step-by-step explanation:
HCF... 132, 154, 176 (Division Method) is 22
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Answer:
Prime factors of 132 = 2² . 3 . 11
Prime factors of 154 = 2 . 7 . 11
Prime factors of 176 = 2⁴ . 11
Common prime factors: 2 , 11
Common prime factors with the lowest exponent: 2¹, 11¹
HCF = 2¹. 11¹= 22.
Steps for HCF(12, 24):
HCF(24, 12) = HCF(12, 24 mod 12) = HCF(12, 0)
HCF(12, 0) = 12 (∵ HCF(X, 0) = |X|, where X ≠ 0)
⇒ HCF(12, 24) = 12
⇒ HCF(HCF(12, 24), 36) = HCF(12, 36)
Steps for HCF(12, 36):
HCF(36, 12) = HCF(12, 36 mod 12) = HCF(12, 0)
HCF(12, 0) = 12 (∵ HCF(X, 0) = |X|, where X ≠ 0)
⇒ HCF(12, 36) = 12
Therefore, the value of HCF of 12, 24, and 36 is 12.
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