Math, asked by aahelibalu13, 10 hours ago

find the HCF... 132, 154, 176 (Division Method)

iii) 12, 24, 36 (Common factor Method / Listing Method) please help its really urgent​

Answers

Answered by cutebrainlystar
2

Step-by-step explanation:

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HCF... 132, 154, 176 (Division Method) is 22

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Answered by vaibhav13550
0

Answer:

Prime factors of 132 = 2² . 3 . 11

Prime factors of 154 = 2 . 7 . 11

Prime factors of 176 = 2⁴ . 11

Common prime factors: 2 , 11

Common prime factors with the lowest exponent: 2¹, 11¹

HCF = 2¹. 11¹= 22.

Steps for HCF(12, 24):

HCF(24, 12) = HCF(12, 24 mod 12) = HCF(12, 0)

HCF(12, 0) = 12 (∵ HCF(X, 0) = |X|, where X ≠ 0)

⇒ HCF(12, 24) = 12

⇒ HCF(HCF(12, 24), 36) = HCF(12, 36)

Steps for HCF(12, 36):

HCF(36, 12) = HCF(12, 36 mod 12) = HCF(12, 0)

HCF(12, 0) = 12 (∵ HCF(X, 0) = |X|, where X ≠ 0)

⇒ HCF(12, 36) = 12

Therefore, the value of HCF of 12, 24, and 36 is 12.

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