Question

Find the HCF 504 and5292 with the help of dividend method

Answer 1

★ $\large{\underline{\sf{Solution:-}}}$

→ $\boxed{\sf{HCF = 252}}$

★ $\large{\underline{\sf{Explanation:-}}}$

→ Now, taking 504:-

$\begin{tabular}{l|r}2&504\\\cline{1-2}2&252\\\cline{1-2}2&126\\\cline{1-2}3&63\\\cline{1-2}3&21\\\cline{1-2}7&7\\\cline{1-2}&1\end{tabular}$

→ Now, taking 5292:-

$\begin{tabular}{l|r}2&5292\\\cline{1-2}2&2646\\\cline{1-2}3&1323\\\cline{1-2}3&441\\\cline{1-2}3&147\\\cline{1-2}7&49\\\cline{1-2}7&7\\\cline{1-2}&1\end{tabular}$

★ To find the HCF, multiply all the prime factors common to both numbers:-

→ 504 = 2 × 2 × 2 × 3 × 3 × 7

→ 5292 = 2 × 2 × 3 × 3 × 3 × 7 × 7

→ HCF = 2 × 2 × 3 × 3 × 7

→ $\boxed{\sf{HCF = 252}}$

Therefore, HCF of 504 and 5292 is 252.

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Answer 2

$\huge\mathtt\red{Answer}$

ʜᴄꜰ ᴏꜰ 504 :-

$\begin{array}{r | 1} 2 & 504\\ \cline{2-2} 2 & 252\\ \cline{2-2} 2 & 126\\ \cline{2-2} 3 & 63\\ \cline{2-2} 3 & 21\\ \cline{2-2} 7 & 7\\ \cline{2-2} & 1\end{array}$

ꜱᴏ,
504 = 2×2×2×3×3×7

ʜᴄꜰ ᴏꜰ 5292 :-

$\begin{array}{r | 1} 2 & 5292\\ \cline{2-2} 2 & 2646\\ \cline{2-2} 3 & 1323\\ \cline{2-2} 3 & 441\\ \cline{2-2} 3 & 147\\ \cline{2-2} 7 & 49\\ \cline{2-2} 7 & 7\\ \cline{2-2} & 1\end{array}$

ꜱᴏ,
5292 :- 2×2×3×3×3×7×7

ᴛᴏ ꜰɪɴᴅ ᴛʜᴇ ʜᴄꜰ, ᴡᴇ ʜᴀᴠᴇ,

2×2×3×3×7
= $\fbox{252}$

ʜᴇɴᴄᴇ ᴛʜᴇ ʜᴄꜰ ᴏꜰ 504 ᴀɴᴅ 5292 ɪꜱ 252.