Find the HCF:
a. 49,91,112
b. 36,126,189
By prime factorization and long division method
Answers
91=7×13
112=2×2×2×2×7
So,the HCF of 49,91 and 112 is 7 by prime factorization method.
Now by long division method
49)91(1
49
__
42)49(1
42
___
07)42(6
42
___
00
Now the HCF of 7 and 112
7)112(16
112
___
×××
Hence the HCF of 49,91 and 112 is 7.
HCF = 7 for 49,91,112 & HCF = 9 for 36,126,189
Step-by-step explanation:
49,91,112
Prime factorization
49 = 7 * 7
91 = 7 * 13
112 = 2 * 2 * 2 * 2 * 7
Common factor = 7
HCF = 7
36 , 126 , 189
36 = 2 * 2 * 3 * 3
126 = 2 * 3 * 3 * 7
189 = 3 * 3 * 3 * 7
Common Factor = 3 * 3 = 9
HCF = 9
Long divison
49 _| 91 |_ 1
49
____
42 _| 49 |_ 1
42
____
7 _| 42 |_ 6
42
___
0
7 _| 112 |_ 16
112
____
0
HCF = 7
126 _| 189 |_ 1
126
____
63 _| 126 |_ 2
126
____
0
____
36 _| 63 |_ 1
36
____
27 _| 36 |_ 1
27
___
9 _| 27 |_ 3
27
____
0
HCF = 9
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