Question

Find the hcf abs lcm of a and b,for the number a=2×3×5×7 and b=2×3×5×11 . and also cheak if hcf (a,b)×lcm(a,b)=a×b

Answer 1

Answer:

I can't answer this question

Explanation:

because I am not cbse board student

Answer 2

Answer:

HCF is the least power common in both,

so HCF of given numbers = 2^3×3^2×5^2

LCM is greatest power

so LCM of given numbers =

2^5×3^7×5^6×7×11

Now LCM×HCF=(2^5×3^7×5^6×7×11)×

(2^3×3^2×5^2)

= 2^8×3^9×5^8×7×11

a×b = (2^5×3^7×5^2×7)×

(2^3×3^2×5^6×11)

= 2^8×3^9×5^8×7×11

Hence a×b=HCF×LCM