Find the hcf&lcf of Each the following pairs of integers and verify that lcm×hcf=product of two numbers a130,364 b850,276 c90,144
Answers
Answer:
Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 (ii) 510 and 92 (iii) 336 and 54
Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.
26 and 91 (ii) 510 and 92 (iii) 336 and 54
Answer:
(i)
26 = 2 x 13
91 =7 x 13
HCF = 13
LCM =2 x 7 x 13 =182
Product of two value 26 x 91 = 2366
Product of HCF and LCM 13 x 182 = 2366
Hence, product of two numbers = product of HCF × LCM
(ii)
510 = 2 x 3 x 5 x 17
92 =2 x 2 x 23
HCF =2
LCM =2 x 2 x3 x 5 x 17 x 23 = 23460
Product of both values 510x92 = 46920
Product of HCF and LCM 2x23460 =46920
Hence, product of two numbers = product of HCF × LCM
(iii)
336 = 2 x 2 x 2 x 2 x 3 x 7
54 = 2 x 3 x 3 x 3
HCF = 2 x 3 = 6
LCM = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 7 =3024
Product of number 336 x 54 =18144
Product of HCF and LCM 6 x 3024 = 18144
Hence, product of two numbers = product of HCF × LCM
please follow me...
and mark brainleist