Question

Find the HCF & LCM 8x3-27 and 4x2-12x +9​

Answer 1

Answer:

(8x^3- 27)/(4X^2 - 9)

To simplify the fraction,

We know that:

(a^3 - b^3) = (a-b) ( a^2 + ab + b^2)

(a^2 - b^2) = (a-b) *(a+b)

LET US factor:

==> (2x-3)(4x^2 + 6x + 9) / (2x-3)(2x+3)

Now reduce similars:

==> (4x^2 + 6x + 9)/(2x+3)

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