Question

find the HCF and factorise 3x2y-6xy+3x2y2 plss give the and fast step by step​

Answer 1

Step-by-step explanation:

Let f(x,y)=4x

2

+3x

2

y−9xy

2

+2y

3

and g(x,y)=x

2

+xy−2y

2

Clearly (x−y)=0 or x=y satisfy both equation, since for x=y makes both equations zero.

Hence, (x−y) is the H.C.F.

Similarly (x+2y)=0 i.e., x=−2y also makes both equations zero.

Thus, (x+2y)(x−y) is the H.C.F.

Answer 2

Answer:

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