Question

find the HCF and LCF of 405, 603 by uaing the algorithm method.

Answer 1

Answer:

Step-by-step explanation ;

603 > 405

603 = 405 * 1 +198

405 = 198 * 2 +9

198 = 9* 22 +0

HCF = 9

Answer 2

BY DIVISION ALGORITM METHOD

Since,

405 < 603

$\therefore$ 603 = 405 × 1 + 198
405 = 198 × 2 + 9
198 = 9 × 22 + 0

HCF = 9

BY PRIME FACTORIZATION METHOD

405 = 3 × 3 × 3 × 3 × 5
603 = 3 × 3 × 67

HCF = 3 × 3
= 9</b>[/tex]

$\huge \boxed{answer = 9}$