Math, asked by mayank4457, 1 year ago

find the HCF and LCM by using forward in question number 27 90​

Answers

Answered by shinchan1304
0

Answer:

27=3×3×3

90=3×3×2×5

hcf=3×3=9

lcm=3×3×3×2×5=270

Answered by яσѕнαη
9

\mathfrak{dear\;user  }

\textsf{question-Find\: the \:LCM \:of \:27 \:and \:90\:. \:Use \:the \:LCM \:to \:find \:their \:HCF. ​}

\mathfrak{here\:is\:the\:solution\:for \:the question  }

\Large{ \begin{array}{c|c} \tt 3 & \sf{ 27,90} \\ \cline{1-2} \tt 3 & \sf { 9,10} \\ \cline{1-2} \tt 3 & \sf{ 3,10} \\ \cline{1-2} \tt 5 & \sf{ 1,10} \\ \cline{1-2} \tt 2 & \sf{ 1,2}\\ \cline{1-2} & \sf{ 1,1 } \end{array}}

lcm=2\times3\times3\times3\times5=270

hcf=3\times3=9

\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS  }10\:thanks\:and \:brainlist

\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}

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