Find the HCF and LCM of 104 4096 and 315 by prime factorization me thod
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104= 2×2×2×13 =2^3×13
4096= 2×2×2×2×2×2×2×2×2×2×2×2 =2^12
315=5×3×3×7=5×7×3^2
HCF(104,4096 and 315)=Product of smallest power of each common factor.
=>1
LCM(104,4096 and 315)=Product of greatest power of each factor.
=>2^12×13×5×7×3^2
=>1,67,73,120 Ans.
4096= 2×2×2×2×2×2×2×2×2×2×2×2 =2^12
315=5×3×3×7=5×7×3^2
HCF(104,4096 and 315)=Product of smallest power of each common factor.
=>1
LCM(104,4096 and 315)=Product of greatest power of each factor.
=>2^12×13×5×7×3^2
=>1,67,73,120 Ans.
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