Question

Find the HCF and LCM of 108 120 253 by prime factorisation method

Answer 1

Answer:

108=2*2*3*3*3

120=2*2*2*3*5

253=11*23

HCF(108,120,253)=1

LCM(108,120,253)=2*2*2*3*3*3*5*11*23

=273240

Step-by-step explanation:

Answer 2

hello here is the answer for the question

108= 2 *2*3*3*3

120 = 2*2*2*3*5

253 = 11*23

therefore ; HCF = 1

   and       LCM = 2*2*2*3*3*3*5*11*23= 27340

hope this is helpful to you ;)

TOODLES :)