Question

find the hcf and lcm of 144,180,192 by prime factorization method

Answer 1

Factors of 144 = 2×2×2×2×3×3

Factors of 180 = 2×2×3×3×5

Factors of 192 = 2×2×2×2×2×2×3

Common factors of 144, 180, 192 = {2,2,3}

LCM (144,180,192) =
2×2×2×2×2×2×3×3×5 = 2880

So, HCF(144,180,192) = 2×2×3 = 12.

Answer 2

This question had 192 too with 144 and 180. So here is the solution for that.

Factors of 144 = 2×2×2×2×3×3

Factors of 180 = 2×2×3×3×5

Factors of 192 = 2×2×2×2×2×2×3

Common factors of 144, 180, 192 = {2,2,3}

LCM (144,180,192) =

2×2×2×2×2×2×3×3×5 = 2880

So, HCF(144,180,192) = 2×2×3 = 12.

If there is any confusion please leave a comment below.